1005_地球人口承载力
#include<iostream>#include<cstdio>using namespace std;int main(){ int x,a,y,b; double z; cin>>x>>a>>y>>b;
/* 设地球现有资源now,每年新增up,每年消耗down 若可持续发展 year*up = z*year*down z = up/down
now + a*up = a*x*down now + b*up = b*y*down
两式相减
a*up-b*up = a*x*down-b*y*down up(a-b) = down(ax - by) up/down = (ax - by)/(a-b)
*/ z=(1.0*a*x-b*y)/(1.0*a-b); printf("%.2f",z);
return 0;}